[Deal] Claim $100 off the 64GB Moto X Pure Edition at Best Buy


Motorola hosts sales very frequently. As for their latest deal, you can grab a 64GB Moto X Pure Edition at Best Buy retail stores or online for $100 off.

If you’re in the market for a new smartphone, but don’t want to break the bank doing so, this deal is as good as you’ll ever find. The Moto X Pure Edition is still one of our favorite smartphones, even though it launched last year. It sports a sleek design, features fast internals, and comes with all the goodies you need such as a built-in microSD card slot.

For a limited time, you can claim the Moto X Pure Edition for $100 off its original retail price at Best Buy. The sale only applies to the 64GB version, which puts the price right on par with the 16GB version. One color model has already sold out so claim the offer now while it lasts!

After applying the $100 off, a brand new 64GB Moto X Pure Edition will cost you only $399 plus tax. Shipping is included for free and will be at an extended rate. To take advantage of this limited time offer, click the link down below.

[Best Buy]

About the Author: Doug Demagistris

Doug was raised in New York and currently attends Muhlenberg College where he is majoring in Accounting. He has been a die-hard Google and Android enthusiast ever since he purchased the Samsung Galaxy Vibrant. Doug strongly prefers Android over competitors for its customization, flat Material Design and exceptional integration with Google Services. Currently, Doug switches between the Samsung Galaxy Note 5 and Nexus 5X, and travels with a Nexus 9. In addition, Doug wears an Android Wear smartwatch and has other gadgets such as a Nexus Player and Cardboard viewer. Aside from writing with Talk Android, Doug enjoys testing new applications, designing concepts and studying Android application development all while attempting to keep up with the rapid world of technology. He’s hopeful that his high productivity will make lives easier and more meaningful. Doug’s dream is to attend Google I/O.